Question

How to generate all permutations of 1, 2 and 3 without repetition in JavaScript

Answer 1

for (let i = 1; i <= 3; i++) {  
     for (let j = 1; j <= 3; j++) {  
          for (let k = 1; k <= 3; k++) {  
              if (i != j && i != k && j != k)  
                  console.log(i + " " + j + " " + k);
          }  
     }  
}  
   
   
   
     
/*
run:
     
"1 2 3"
"1 3 2"
"2 1 3"
"2 3 1"
"3 1 2"
"3 2 1"
   
*/

 

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