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How to calculate the perimeter and the area of scalene triangle in VB.NET

1 Answer

0 votes
Module Module1

    Sub Main()

        Dim a_base As Integer = 3, b_left_side As Integer = 4, c_right_side As Integer = 5

        Dim perimeter As Double = a_base + b_left_side + c_right_side
        Console.WriteLine("Perimeter = {0:F2}", perimeter)

        Dim semi_perimeter As Double = (a_base + b_left_side + c_right_side) / 2
        Dim area_triangle1 As Double = Math.Sqrt(semi_perimeter * (semi_perimeter - a_base) *
                                                                 (semi_perimeter - b_left_side) *
                                                                 (semi_perimeter - c_right_side))
        Console.WriteLine("Area triangle1 = {0:F2}", area_triangle1)

        Dim b_base As Integer = 4, a_right_side As Integer = 6, angle_ab As Integer = 55
        Dim area_triangle2 As Double = (a_right_side * b_base *
                                                        Math.Sin((Math.PI / 180) *
                                                        angle_ab)) / 2
        Console.WriteLine("Area triangle2 = {0:F2}", area_triangle2)

        Dim height As Integer = 5
        b_base = 8
        Dim area_triangle3 As Double = (b_base * height) / 2
        Console.WriteLine("Area triangle3 = {0:F2}", area_triangle3)

    End Sub

End Module

'run:
'
'Perimeter = 12.00
'Area triangle1 = 6.0
'Area triangle2 = 9.83
'Area triangle3 = 20.0

 



answered Feb 19, 2016 by avibootz
edited Feb 19, 2016 by avibootz

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