Question

How to print (output) one-dimensional int array elements in C

Answer 1

#include <stdio.h>

#define LEN 5

int main(void)
{
	int arr[LEN] = { 2, 234, 1, 800, 100 };
	int i;

	// Print all elements 
	for (i = 0; i < sizeof(arr)/sizeof(arr[0]); i++) 
		printf("arr[%d] = %d\n", i, arr[i]);

    return 0;
}
  
    
/*
      
run:

arr[0] = 2
arr[1] = 234
arr[2] = 1
arr[3] = 800
arr[4] = 100

*/

 

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Answer 2

#include <stdio.h>
 
#define LEN 5
 
int main(void)
{
    int arr[LEN] = { 2, 234, 1, 800, 100 };
    int arr_size;
 
	arr_size = sizeof(arr)/sizeof(arr[0]);
 
    // Print all elements 
    for (int i = 0; i < arr_size; i++) 
        printf("arr[%d] = %d\n", i, arr[i]);
 
    return 0;
}
   
     
/*
       
run:
 
arr[0] = 2
arr[1] = 234
arr[2] = 1
arr[3] = 800
arr[4] = 100
 
*/

 

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Answer 3

#include <stdio.h>
 
#define LEN 5
 
int main(void)
{
    int arr[LEN] = { 2, 234, 1, 800, 100 };
 
    // Print all elements 
    for (int i = 0; i < LEN; i++) 
        printf("arr[%d] = %d\n", i, arr[i]);
 
    return 0;
}
   
     
/*
       
run:
 
arr[0] = 2
arr[1] = 234
arr[2] = 1
arr[3] = 800
arr[4] = 100
 
*/

 

70+ SQL courses for beginners and professionals