Question

How to sort the digits of a number in ascending order with Java

Answer 1

import java.util.Set;
import java.util.HashSet;
 
public class SortTheDigitsOfANumberInAscendingOrder_Java {
    public static void main(String args[]) {
        int n = 4213;
 
        Set<Integer> hset = new HashSet<Integer>(); 
         
        for (int i = n; i > 0; i /= 10)
            hset.add(i % 10);
         
        n = 0;
        for (Integer x : hset) {
             n = n * 10 + x;
        }
         
        System.out.println(n);
    }
}
 
 
 
/*
run:
 
1234
 
*/

 

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