Question

How to extract all numbers from string in Java

Answer 1

public class MyClass {
    public static void main(String args[]) {
        String s = "4hjdsf72q1p0on8mqjava993";
        
        String numbers = s.replaceAll("[^\\d]", " "); 
  
        numbers = numbers.trim(); 

        numbers = numbers.replaceAll(" +", " "); 
        
        String[] numbersArr = numbers.split(" ");
  
        for (String item : numbersArr) {
            System.out.println(item);
        }
    }
}



/*
run:

4
72
1
0
8
993

*/

 

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Answer 2

public class MyClass {
    public static void main(String args[]) {
        String s = "4hjdsf72q1p0on8mqjava993";
        
        String numbers = s.replaceAll("[^\\d]", " "); 
  
        numbers = numbers.trim(); 

        numbers = numbers.replaceAll(" +", " "); 
        
        String[] numbersArr = numbers.split(" ");
  
        for (String item : numbersArr) {
            int n = Integer.parseInt(item);
            System.out.println(n);
        }
    }
}



/*
run:

4
72
1
0
8
993

*/

 

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Answer 3

import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class MyClass {
    public static void main(String args[]) {
        String s = "412hjdsf72q1p0on8mqjava9953";
 
        Pattern p = Pattern.compile("\\d+");
        Matcher m = p.matcher(s);
        
        while (m.find()) {
            System.out.println(m.group());
        }
    }
}
 
 
 
 
/*
run:
 
412
72
1
0
8
9953
 
*/

 

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