Question

How to throw an exception in C#

Answer 1

using System;

public class Number {
    int[] arr = { 4, 7, 0, 6, 1, 8 };
    
    public int GetNumber(int i) {
        if (i < 0 || i >= arr.Length) {
            throw new IndexOutOfRangeException();
        }
        return arr[i];
    }
}


public class Program {
   public static void Main() {
      var o = new Number();
      
      try {
          Console.WriteLine(o.GetNumber(3));
          Console.WriteLine(o.GetNumber(99));
      }
      catch (IndexOutOfRangeException ex) {
         Console.WriteLine(ex.GetType().Name);
      }
   }
}




/*
run

6
IndexOutOfRangeException

*/

 

70+ SQL courses for beginners and professionals