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How to call base class constructor when creating instance of derived class in C#

1 Answer

0 votes
using System;

public class BaseClass {

    public BaseClass() {
        Console.WriteLine("BaseClass()");
    }

    public BaseClass(int _n) {
        Console.WriteLine("BaseClass(int _n)");
    }
}

public class DerivedClass : BaseClass {
    public DerivedClass() : base() {} // call BaseClass.BaseClass()

    public DerivedClass(int i) : base(i) {} // call BaseClass.BaseClass(int _n)

    static void Main()
    {
        DerivedClass o1 = new DerivedClass();
        DerivedClass o2 = new DerivedClass(12);
        
        Console.WriteLine(o1);
        Console.WriteLine(o2);
    }
}




/*
run:

BaseClass()
BaseClass(int _n)
DerivedClass
DerivedClass

*/

 



answered Nov 22, 2020 by avibootz

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