Question

How to use case statement in Ruby

Answer 1

def m(val)
    return case val
        when 0..3 then "0..3"
        when 4..7 then "4..7"
        when 12..14 then "12..14"
        else "Not in case"
    end
end

print m(0), "\n"
print m(5), "\n"
print m(14), "\n"
print m(50), "\n"



# run:
#
# 0..3
# 4..7
# 12..14
# Not in case

 

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