How to reverse a linked list in Go

1 Answer

0 votes
package main
 
import "fmt"
 
type Node struct {
    prev *Node
    next *Node
    val interface{}
}
 
type LL struct {
    head *Node
    tail *Node
}
 
func (ll *LL) Insert(val interface{}) {
    linklist := &Node {
        next: ll.head,
        val: val,
    }
    if ll.head != nil {
        ll.head.prev = linklist
    }
    ll.head = linklist
 
    ltail := ll.head
    for ltail.next != nil {
        ltail = ltail.next
    }
    ll.tail = ltail
}
 
func (ll *LL) Print() {
    llist := ll.head
    for llist != nil {
        fmt.Printf("%+v - ", llist.val)
        llist = llist.next
    }
    fmt.Println()
}

func (ll *LL) Reverse() {
    current := ll.head
    var prev *Node
    ll.tail = ll.head
 
    for current != nil {
        next := current.next
        current.next = prev
        prev = current
        current = next
    }
    ll.head = prev
}

 
func main() {
    linklist := LL{}
    
    linklist.Insert(6)
    linklist.Insert(1)
    linklist.Insert(87)
    linklist.Insert(34)
    linklist.Insert(982)
    linklist.Insert(7)
    linklist.Insert(3)
    linklist.Insert(99)    
    
    linklist.Print()
    
    linklist.Reverse()

    linklist.Print()

}




/*
run:

99 - 3 - 7 - 982 - 34 - 87 - 1 - 6 - 
6 - 1 - 87 - 34 - 982 - 7 - 3 - 99 - 

*/

 



answered Aug 23, 2020 by avibootz
...