How to count the unique elements of an array in C

1 Answer

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#include <stdio.h>
 
int main()
{
    int arr[] = {4, 1, 2, 8, 9, 5, 1, 7, 8, 8, 6};
    int frequency[10] = {0};
    int size = sizeof(arr) / sizeof(arr[0]);
      
    for (int i = 0; i < size; i++) {
        frequency[arr[i]]++;
    }

    int count = 0;
    for (int i = 0; i < 10; i++) {
        if (frequency[i] == 1)
            count++;
    }
    printf("%d\n", count);
         
    return 0;
}
    
   
    
    
/*
run:
    
6
   
*/
 

 



answered Jul 6, 2020 by avibootz
edited Apr 18, 2022 by avibootz

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