Question

How to use super property in extends class methods with JavaScript ES6

Answer 1

class Person {
    constructor(name) {
        this.name = name;
    }
    toString() { 
        return `Person: ${this.name}`;
    }
}

class Worker extends Person {
    constructor(name, age) {
        super(name);
        this.age = age;
    }
    toString() {
        return `${super.toString()} (${this.age})`; 
    }
}

const obj = new Worker('Tom', 47);

console.log(obj.toString()); 



 
/*
run:
      
Person: Tom (47)
 
*/

 

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