How to count digits, whitespace and all other characters from input in C

1 Answer

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#include <stdio.h>

int main(int argc, char **argv) 
{ 
    int ch, nwhite, nother;
    int ndigit[10];
    
    nwhite = nother = 0;
    
    for (int i = 0; i < 10; i++)
         ndigit[i] = 0;
    
    while ( (ch = getchar()) != EOF) // Enter & Ctrl + c to exit
    {
        if (ch >= '0' && ch <= '9')
            ndigit[ch - '0']++;
        else if (ch == ' ' || ch == '\n' || ch == '\t')
                 nwhite++;
             else
                nother++;
    }
    printf("\ndigits:");
    for (int i = 0; i < 10; i++)
         printf(" %d", ndigit[i]);
        
    printf(", white space = %d, other = %d\n", nwhite, nother ) ;
    
    return 0;
}

/*
  
run:
   
abc 1233 @#$    XYZ

digits: 0 1 1 2 0 0 0 0 0 0, white space = 7, other = 9

*/

 



answered Oct 20, 2015 by avibootz

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