Question

How to initialize array with a range of int numbers in Python

Answer 1

import array 

a = array.array('i', range(5)) # i = int

print(a)   
print(a[1:4])
print(a[2:3])
print(a[0])
print(a[3])




'''
run:
 
array('i', [0, 1, 2, 3, 4])
array('i', [1, 2, 3])
array('i', [2])
0
3

'''

 

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Answer 2

import array 
 
a = array.array('i', range(4, 9)) # i = int
 
print(a)   
print(a[1:4])
print(a[2:3])
print(a[0])
print(a[3])
 
 
 
 
'''
run:
  
array('i', [4, 5, 6, 7, 8])
array('i', [5, 6, 7])
array('i', [6])
4
7

'''

 

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Answer 3

import array 
 
a = array.array('i', range(4, 17, 3)) # i = int
 
print(a)   
print(a[1:4])
print(a[2:3])
print(a[0])
print(a[3])
 
 
 
 
'''
run:
  
array('i', [4, 7, 10, 13, 16])
array('i', [7, 10, 13])
array('i', [10])
4
13

'''

 

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