Question

How to calculate square root (or floor square if not perfect square) of an integer in Python

Answer 1

def sqrt_(n):
    if (n == 0 or n == 1):
        return n 
   
    i = 1 
    sq = 1
     
    while (sq <= n):
      i += 1
      sq = i * i
    
    return i - 1; 


print(sqrt_(9));
print(sqrt_(5));
print(sqrt_(26));
print(sqrt_(16));



'''
run:

3
2
5
4

'''

 

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