How to count appearance of specific value in int array using C

1 Answer

0 votes
#include <stdio.h>

int count_appearance(int arr[], int arr_size, int value) {
    int count = 0;
    for (int i = 0; i < arr_size; i++)
        if (arr[i] == value) {
            count++;
        }
        
    return count;
}

int main()
{
    int arr[] = {1, 2, 3, 4, 4, 4, 5, 7, 8, 8, 8, 8, 9, 9}; 
    int arr_size = sizeof(arr)/sizeof(arr[0]);

    printf("%i\n", count_appearance(arr, arr_size, 4));
    printf("%i\n", count_appearance(arr, arr_size, 2));
    printf("%i\n", count_appearance(arr, arr_size, 8));
    printf("%i\n", count_appearance(arr, arr_size, 9));

    return 0;
}



/*
run:

3
1
4
2

*/

 



answered Mar 31, 2019 by avibootz

Related questions

1 answer 219 views
1 answer 195 views
1 answer 194 views
1 answer 172 views
2 answers 264 views
...