How to find non-repeated characters in a string with Python

2 Answers

0 votes
def printNonRepeatedCharacters(s):
    ascii_count = [0] * 256
 
    for i in range (len(s)):
        if (s[i] != ' '):
            ascii_count[ord(s[i])] += 1
        
    n = i
 
    for i in range(n):
        if (ascii_count[ord(s[i])] == 1):
            print(s[i], end = "")
             
 
s = "python programming"
 
printNonRepeatedCharacters(s)
 
 
'''
run:
 
ythai
 
'''

 



answered Feb 10, 2019 by avibootz
edited Feb 10, 2019 by avibootz
0 votes
def getNonRepeatedCharacters(s):
    ascii_count = [0] * 256

    for i in range (len(s)):
        if (s[i] != ' '):
            ascii_count[ord(s[i])] += 1
        
    n = i

    new_s = "";
    for i in range(n):
        if (ascii_count[ord(s[i])] == 1):
            new_s += s[i];
            
    return new_s
            


s = "python programming"

new_s = getNonRepeatedCharacters(s)
print(new_s)


'''
run:

ythai

'''

 



answered Feb 10, 2019 by avibootz
edited Feb 10, 2019 by avibootz

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