Question

How to create an empty list and append X times new elements of length Y to each element in Python

Answer 1

row = 3
col = 4
lst = []
for i in range(row):
    lst.append([0] * col)

print(lst)


'''
run:

[[0, 0, 0, 0], [0, 0, 0, 0], [0, 0, 0, 0]]

'''

 

70+ SQL courses for beginners and professionals

Answer 2

row = 3
col = 4
lst = []
for i in range(row):
    lst.append([0] * col)

lst[0][0] = 1
lst[1][1] = 2
lst[2][2] = 3

print(lst)


'''
run:

[[1, 0, 0, 0], [0, 2, 0, 0], [0, 0, 3, 0]]

'''

 

70+ SQL courses for beginners and professionals

Answer 3

row = 3
col = 4
lst = []
for i in range(row):
    lst.append([0] * col)

lst[0][0] = 1
lst[1][1] = 2
lst[2][2] = 3

for row in lst:
    for col in row:
        print(col, end=" ")
    print(end="\n")


'''
run:

1 0 0 0 
0 2 0 0 
0 0 3 0

'''

 

70+ SQL courses for beginners and professionals