Question

How to use const_cast on a const reference in C++

Answer 1

#include <iostream>

using std::cout;
using std::endl;

void square_root(const int &n) {

	const_cast<int &> (n) = n * n;
}
int main()
{
	int n = 9;

	square_root(n);

	cout << n << endl;

	return 0;
}


/*
run:

81

*/

 

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