Question

How to check qualify as unique number that must contain one of each digit up to the length of himself in PHP

Answer 1

function is_unique_digital($number, $zero=false)
{
    $number = str_split($number);
    sort($number);
     
    return implode($number) === substr('0123456789', !$zero, count($number));
}

if (is_unique_digital("12342"))
    echo "1. true<br/>";
else
    echo "1. false<br/>";

if (is_unique_digital("1142"))
    echo "2. true<br/>";
else
    echo "2. false<br/>";
    
if (is_unique_digital("1342"))
    echo "3. true<br/>";
else
    echo "3. false<br/>";
 
if (is_unique_digital("13042", true))
    echo "4. true<br/>";
else
    echo "4. false<br/>";
    
if (is_unique_digital("1042", true))
    echo "5. true<br/>";
else
    echo "5. false<br/>";
    
if (is_unique_digital("16345"))
    echo "6. true<br/>";
else
    echo "6. false<br/>";

if (is_unique_digital("162345"))
    echo "7. true<br/>";
else
    echo "7. false<br/>";

 
/*
run: 
  
1. false
2. false
3. true
4. true
5. false
6. false
7. true
  
*/ 

 

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Answer 2

function is_unique_digital($number)
{
    $number = str_split($number);
    sort($number);
    
    $start = 1;
    if ("0" === $number[0])
        $start = 0;
    
    return implode($number) === substr('0123456789', $start, count($number));
}

if (is_unique_digital("12342"))
    echo "1. true<br/>";
else
    echo "1. false<br/>";

if (is_unique_digital("1142"))
    echo "2. true<br/>";
else
    echo "2. false<br/>";
    
if (is_unique_digital("1342"))
    echo "3. true<br/>";
else
    echo "3. false<br/>";
 
if (is_unique_digital("13042"))
    echo "4. true<br/>";
else
    echo "4. false<br/>";
    
if (is_unique_digital("1042"))
    echo "5. true<br/>";
else
    echo "5. false<br/>";
    
if (is_unique_digital("16345"))
    echo "6. true<br/>";
else
    echo "6. false<br/>";

if (is_unique_digital("162345"))
    echo "7. true<br/>";
else
    echo "7. false<br/>";

 
/*
run: 
  
1. false
2. false
3. true
4. true
5. false
6. false
7. true
  
*/   

 

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