Question

How to output an object for debugging in PHP

Answer 1

$o = new stdClass();
$o->value = 'PHP Programming';
$o->test = 100;

echo "<pre>";
print_r($o);
echo "</pre>";

/*
run: 
 
stdClass Object
(
    [value] => PHP Programming
    [test] => 100
)
 
*/

 

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Answer 2

$o = new stdClass();
$o->value = 'PHP Programming';
$o->test = 100;
 
echo '<pre>' . print_r($o, true) . '</pre>';

/*
run: 
 
stdClass Object
(
    [value] => PHP Programming
    [test] => 100
)
 
*/

 

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Answer 3

$o = new stdClass();
$o->value = 'PHP Programming';
$o->test = 100;
 
header('Content-Type: text/plain; charset=utf-8');
print_r($o);

/*
run: 
 
stdClass Object
(
    [value] => PHP Programming
    [test] => 100
)
 
*/

 

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Answer 4

$o = new stdClass();
$o->value = 'PHP Programming';
$o->test = 100;
 
var_dump($o); 

/*
run: 
 
object(stdClass)#1 (2) { ["value"]=> string(15) "PHP Programming" ["test"]=> int(100) }
 
*/

 

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Answer 5

$o = new stdClass();
$o->value = 'PHP Programming';
$o->test = 100;
 
var_export($o); 

/*
run: 
 
stdClass::__set_state(array( 'value' => 'PHP Programming', 'test' => 100, ))
 
*/

 

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Answer 6

$o = new stdClass();
$o->value = 'PHP Programming';
$o->test = 100;
 
echo var_export($o, true); 

/*
run: 
 
stdClass::__set_state(array( 'value' => 'PHP Programming', 'test' => 100, ))
 
*/

 

70+ SQL courses for beginners and professionals