Question

How to check odd or even using bitwise operator in C#

Answer 1

using System;

namespace ConsoleApplication1
{
    class Program
    {
        static void Main(string[] args)
        {
            try
            {
                Console.Write("Enter a number: ");
                int n = Convert.ToInt32(Console.ReadLine());
                if (Convert.ToInt32(n & 1) == 1)
                    Console.WriteLine("Odd");
                else
                    Console.WriteLine("Even");
            }
            catch (Exception ex)
            {
                Console.WriteLine(ex.Message);
            }
        }
     }
}

/*
run1:
   
Enter a number: 10
Even

run2:

Enter a number: 13
Odd
  
*/

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Answer 2

using System;

namespace ConsoleApplication1
{
    class Program
    {
        static void Main(string[] args)
        {
            try
            {
                Console.Write("Enter a number: ");
                int n = Convert.ToInt32(Console.ReadLine());
                if ((n & 1) == 1)
                    Console.WriteLine("Odd");
                else
                    Console.WriteLine("Even");
            }
            catch (Exception ex)
            {
                Console.WriteLine(ex.Message);
            }
        }
     }
}

/*
run1:
   
Enter a number: 10
Even

run2:

Enter a number: 13
Odd
  
*/

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