Question

How to check if a number is strong number or not in C++

Answer 1

#include <iostream>

using namespace std;

// Strong numbers are the numbers that the sum of factorial of its digits 
// is equal to the original number

// 145 is a strong number: 1 + 24 + 120 = 145

long factorial(int n);

int main()
{
	int n = 145, reminder, sum = 0, tmp;

	tmp = n;

	while (n)
	{
		reminder = n % 10;
		sum = sum + factorial(reminder);
		n /= 10;
	}
	if (sum == tmp)
		cout << tmp << " is a strong number" << endl;
	else
		cout << " is not a strong number" << endl;

	return 0;
}

long factorial(int n)
{
	long fact = 1;

	for (int i = 2; i <= n; i++)
		fact = fact * i;

	return fact;
}

/*
run:

145 is a strong number

*/

 

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