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How to check if a number is armstrong number or not in VB.NET

1 Answer

0 votes
Module Module1

    ' An Armstrong number of three digits is an integer that the sum 
    ' of the cubes of its digits Is equal to the number itself

    ' 371 Is an Armstrong number 3**3 + 7**3 + 1**3 = 371

    Sub Main()

        Dim n As Integer = 371, reminder As Integer, sum As Integer = 0, tmp As Integer

        tmp = n

        While n <> 0

            reminder = n Mod 10
            n = n \ 10
            sum = sum + (reminder * reminder * reminder)
        End While

        If (sum = tmp) Then
            Console.WriteLine("{0} is an Armstrong number", tmp)
        Else
            Console.WriteLine("{0} is not an Armstrong number", tmp)
        End If

    End Sub

End Module

' run:
' 
' 371 is an Armstrong number

 



answered May 6, 2017 by avibootz
edited May 6, 2017 by avibootz

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