Question

How to convert array of hex strings to int and char in C

Answer 1

#include <stdio.h>
#include <stdlib.h>

int main(void)
{
    char hexarr[][3] = { "61", "7A", "20", "0A", "49" };
    int i, n;
    
    for (i = 0; i < sizeof(hexarr)/sizeof(hexarr[0]); i++)
    {
        n = (int)strtol(&hexarr[i][0], NULL, 16);
        printf("%d - ", n);
        printf("%c\n", n);
    }    
   
    return 0;
}

/*
run:
  
97 - a
122 - z
32 -
10 -

73 - I

*/

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Answer 2

#include <stdio.h>
#include <stdlib.h>

int main(void)
{
    char hexarr[][3] = { "61", "7A", "20", "0A", "49" };
    int i, n;
    
    for (i = 0; i < sizeof(hexarr)/sizeof(hexarr[0]); i++)
    {
        sscanf(&hexarr[i][0], "%x", &n);
        printf("%d - ", n);
        printf("%c\n", n);
    }   
   
    return 0;
}

/*
run:
  
97 - a
122 - z
32 -
10 -

73 - I

*/

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