Question

How to split a string into String array using a set of characters in Java

Answer 1

package javaapplication1;

public class JavaApplication1 {

    public static void main(String[] args) {

        try {

            String str = "java,c,@c++:,php!,c#,c-3po";

            String arr[] = str.split("[,:@!]");
            for (String s : arr) {
                System.out.println(s);
            }

        } catch (Exception e) {
            System.out.println(e.toString());
        }
    }
}

/*
               
run:
  
java
c

c++

php

c#
c-3po
      
 */

 

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Answer 2

package javaapplication1;

public class JavaApplication1 {

    public static void main(String[] args) {

        try {

            String str = "java,c,@c++:,php!,c#,c-3po";

            String arr[] = str.split("[,:@!]");

            for (String s : arr) {
                if (!"".equals(s))
                    System.out.println(s);
            }

        } catch (Exception e) {
            System.out.println(e.toString());
        }
    }
}

/*
               
run:
  
java
c
c++
php
c#
c-3po
      
 */

 

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Answer 3

package javaapplication1;
 
import java.util.ArrayList;
import java.util.Arrays;
import java.util.Collections;
import java.util.List;
 
public class JavaApplication1 {
 
    public static void main(String[] args) {
 
        try {
 
            String str = "java,c,@c++:,php!,c#,c-3po";
 
            String arr[] = str.split("[,:@!]");
 
            final List<String> list = new ArrayList<String>();
            Collections.addAll(list, arr);
            list.removeAll(Arrays.asList(""));
            arr = list.toArray(new String[list.size()]);
 
            for (String s : arr) {
                System.out.println(s);
            }
 
        } catch (Exception e) {
            System.out.println(e.toString());
        }
    }
}
 
/*
                
run:
   
java
c
c++
php
c#
c-3po
       
 */

 

70+ SQL courses for beginners and professionals