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How to compute the total number of combinations when choosing 7 numbers out of 33 in Scala

1 Answer

0 votes
/**
 * Computes the number of combinations C(n, r):
 *
 *     C(n, r) = n! / (r! * (n - r)!)
 *
 * The calculation is performed incrementally to avoid
 * computing large factorials.
 *
 * @param n Total number of items.
 * @param r Number of items chosen.
 * @return The number of combinations.
 */
def combinations(n: Long, r: Long): Long =
  // Use symmetry: C(n, r) == C(n, n - r)
  val k: Long = math.min(r, n - r)

  var result: Long = 1

  /*
   * Compute:
   *
   *   n × (n - 1) × ... × (n - k + 1)
   *   --------------------------------
   *           1 × 2 × ... × k
   *
   * Dividing at each step keeps intermediate values
   * smaller than they would be using factorials.
   */
  for i <- 0L until k do
    result *= (n - i)
    result /= (i + 1)

  result

@main def lotteryCombinations(): Unit =
  val totalNumbers: Long = 33
  val chosenNumbers: Long = 7

  val totalCombinations: Long =
    combinations(totalNumbers, chosenNumbers)

  println(
    s"C($totalNumbers, $chosenNumbers) = $totalCombinations"
  )


/*
run:

C(33, 7) = 4272048

*/

 



answered 1 day ago by avibootz

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