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How to compare two float arrays using a tolerance in Scala

1 Answer

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/*
    Compare two float arrays element-by-element using a tolerance.
    Floating‑point values often differ slightly due to rounding,
    so two numbers are considered "equal" when their absolute
    difference is below the chosen threshold.
*/

object CompareFloatArraysWithTolerance {

  // Compares two float arrays and returns true if all elements match within tolerance
  def compareFloatArrays(a: Array[Float], b: Array[Float], tolerance: Float): Boolean = {

    // If lengths differ, arrays cannot be equal
    if (a.length != b.length) {
      false
    } else {
      // Use zip + forall to avoid non-local returns and keep the logic clear
      a.zip(b).forall { case (x, y) =>
        val diff: Float = math.abs(x - y)
        diff <= tolerance
      }
    }
  }

  // Prints the comparison result
  def printComparison(result: Boolean): Unit = {
    if (result)
      println("Arrays are equal within tolerance.")
    else
      println("Arrays differ.")
  }

  def main(args: Array[String]): Unit = {

    // Example arrays
    val floatArr1: Array[Float] = Array(
      12314.9872f,
      3.14f,
      12387.91371f,
      8876.579013f
    )

    val floatArr2: Array[Float] = Array(
      12314.9872f,
      3.14f,
      12387.91372f,
      8876.579013f
    )

    // Tolerance chosen for comparison
    val tolerance: Float = 0.001f

    // Perform comparison
    val result: Boolean = compareFloatArrays(floatArr1, floatArr2, tolerance)

    // Output result
    printComparison(result)
  }
}


/*
run:

Arrays are equal within tolerance.

*/

 



answered Sep 8 by avibootz
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